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Maths essay questions

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2018 WAEC SSCE Further more Maths Essay/Essay Questions & Right answers On Farther maths 2018

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Around this specific posting are tested routinely repetitive Further Maths Doubts & Maths composition inquiries to get 2018 May/June SSCE examination that will maintains with 9/4/2018.  Acquire these folks for an individual's handy ideas and additionally a person really are certain in some sort of substantial mark through this specific exams.

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Displayed at this point are actually Even further Maths  queries in addition to solutions applicable to be able to 9/4/2018 Extra Assessment Questions.

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2018 WAEC SSCE Further more Maths Essay/Essay Issues & Solutions Regarding Deeper maths 2018

Farther MATHS OBJ:

1-10: BBADDBABDA

11-20: ACBABDBDAB

21-30: BDDBCBACCD

31-40: ACBDACDBAB

1a)

8m + 2³m = 1/4

2²m + 2²m = 2-²

4³m = 2-²

Equate the actual base

6m = – 2

m = -2/4 = -1/3

1b)

log15 bottom Five = x

a = log15 base/log4 bottom 10 = 1.1761/0.6020

= 1.9536

hence a somewhere around 1.954

========

2a)

(-2) = m(-2)² + n(-2)+2=0

4m-2n = – – – – – – – – (1)

F(1) = m(1)²+n(1)+2=3

m+n+2=3

m+n=3-2

m+n=1 – – – – – – – – – – – -(2)

Times Associate (2) as a result of 4

4m+4n=4 – – – – – – – – – – (3)

4m-2n= -2

-4m+4n=4/-6n = – 6

n=1

============

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2018 WAEC SSCE Further more Maths Essay/Essay Issues writing polemic essay Advice At Farther maths 2018

4)

Offered y= 5/x² + 3

b = 5(x² +3)-1

dy/dx = anxn-1

b = 5(x² + 3)-1

dy = 5(-1) (x2 +3)-1^1

dy/dx = 10x (x² + 3)-²

dy/dx = – 10/(x² +3)²

============

5a)

^nP5 ÷ ^nC4 = 24

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÷ n!/(n-4)!4! =24

n!/(n-5)!

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* (n-4)!4!/n! =24

(n-4)!4!/(n-5)!=24

(n-4)(n-5)!4!/(n-5)!

FEW TOPICS?

= 24

n-4=1

n=4+1

n=5

b)PR= 5C3 (1/6)³ (5/6)^5-3

5!/(5-3)!3! (1/6)³ (5/6)²

5!/2!3!

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(1/6)³ (5/6)²

10 (1/216) (25/36)

=0.03215

Advertising = 1-0.03215

=0.9678

==========

6) try to make a good family table containing

MARKS,TALLY,F & FX

Within f – 2,9,4,2,2,1

According to Forex – 2,18,12,8,10,6

€F= 20

€FX = 56

6b) Signify = articles in consumer credit scores Or €f

= 56 And 20

= 2.8

==============

7)

Given

h=15.4t-4.9t

Pace V=dh/dt =15.4-9.8t

For maximal stature V=0

Thus 15.4-9.8t=0

9.8t=15.4

t=15.4/9.8

t=1.6secs

Time frame so that you can attain utmost top might be 1.6secs

7b)

maximal h=15.4t-9.4t^2

15.4(1.6)-4.9(1.6)^2

22.64-12.544

=12.096

Max top = 12.1m

============

9a)X+6/(x+1)^2 = A/x+1 + B/(x+1)² + C/(x+1)³

X+6/ ~(x+1)³~ =A(x+1)² + B(x+1) + j / ~(x+1)³~

X+6 =A (x+1)² + B(x+1) + C

Allow X+1=0X=-1

-1+6= A new (-1+1)² + B(-1+1) +C

maths dissertation questions C

Therefore:- C=5

X+6= A(X2+2x+1) + Bx + p + C

X+6= Ax²+2Ax+A+Bx+B+C

researching the particular coefficient connected with X²

A=0

Judging that coefficient from X

1=2A+B

1=2(0)+B

Self principle within nursing rehearse essay x+6/(x+3)² = o/x+1 + 1/(x+1)² + 5(x+1)³

1/(x+1)² + 5/(x+1)³

============

10a)

3x^2+x-2 <= 0 3x^2+3x-2x-2 <= 0 3x(x+1) -2 (x+1) <= 0 (3x-2)(x+1) <= 0

3x-2 <= 0 and 8+1 <= 0

2018 WAEC SSCE Further more Maths Essay/Essay Queries & Resolutions Relating to Deeper maths 2018

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2018 WAEC SSCE More Maths Essay/Essay Problems & Right answers Upon Even more maths 2018

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